Re: Psionic help

>> ...........................  For a given amount of antimatter (or
>> contra-terrene matter) m, the reaction optimally converts a mass of 2m
>> (the antimatter plus an equivalent amount of normal, or terrene matter)
>> into energy.  The relationship is shown mathematically with the famous
>> equation:
>>                 2
>>           E = mc                                   (1)
>>
>> where E is the energy produced, m is the mass, and c is the speed of light
>> in a vacuum (approximately 3e8 m/s).  As you can see, even a small amount
>> of mass represents a *huge* (at least, in human terms) amount of energy.
>>
>>      In the above example of 1 mg of antimatter, the reaction would
>> involve 2 mg of mass (don't forget your normal matter), so the energy is
>> (using cgs):
>>
>>           E = (2e-3) * (3e10)
>>             = 6e7 ergs
>>
>>      Not bad, but not catastophic, either.  Don't forget, in the example
>
>The TOTAL CONVERSION statement is correct, and the formula is correct,
>but the numbers plugged into it are WAY off.  The Speed-of-Light (3e8 m/s)
>squared is 9e16, not 3e10 (remember, (x^y)^z = (x^z)^(y*z)).  Therefore,
>using MKS units:
>
>        E = (2e-3) * (9e16)
>          = 1.8e14 joules (= 1.8e21 ergs, since 1 joule=1e7 ergs)
>
>not 6e7 ergs.  And since that amount of energy would make plasma of a
>Plankwell-class battleship, well, if that's not catastrophic, then I don't
>want to be around for something that is :-).  Seriously, according to The
>Encyclopaedia Britannica (15th Ed., 1987), in Vol. 16, page 520, Column 1,
>the total energy (including radiation) generated by the 20-kiloton bomb
>dropped on Hiroshima was about 1e13 joules (1e7 Kw-Hrs.).  If we assume
>(based on that data) that there are 5e12 joules released per kiloton of
>nuclear detonation (1e13/20), and that any increase is linear, then the
>total conversion reaction postulated above would be roughly eqaul to a
>200 kiloton nuclear detonation.

except you got the figures wrong too!

E=(2e-6)*(9e16) {it's two *milligrams*, not two *grams!!}

E= 1.8e11 joules

So we get about .36 kT using your figures  for joules/kT.

But your figures disagree with themselves. 1e13 joules = 2.7e6 kW-hr.

Since I don't have the same edition of the Brittanica, I can't check
your reference because you didn't give the name of the article!

I can't find any of my references at the moment, but I remember that
1 MT = 4.2e??? ergs. So we have a problem.

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