Re: On reactionless drives
In reply to #1257 Re: On reactionless drives by Adrian Hurt
Replies:
- #1269 Re: Reactionless drives by Adrian Hurt
Adrian Hurt writes: >I think what Bertil was trying to say is, what is wrong with turning a ship >from having X megajoules of energy stored as potential energy, to a ship >having .9 X megajoules of kinetic energy and .1 X megajoules of waste energy >(e.g. heat) without having to dump a load of stuff out of the back to satisfy >Newton? This doesn't create energy out of nothing, and doesn't violate >conservation of energy. ^^^^^^^^^^^^^^^ Yes it does. I posted a detailed example showing why recently. Even if you use Bertil's idea of (Energy needed for drive = KE added to ship) it doesn't work because you need a non-accelerating reference frame to measure KE. Example: Suppose you have your ship between planets A and B, which are moving with respect to one another. We now have to choose a frame of reference, say A. Say the velocity of B with respect to A is 1e3 m/s. The KE of ship relative to A is 0, and relative to B is 5e5*M joules. The ship now accelerates to 1e3 m/s relative to A, in the direction opposite to B's motion. Now the KE of the ship relative to A is K1 = 5e5*M joules, where M is the mass of the ship, so we expend (K1 + waste) joules to power the drive. However our velocity relative to B is now 2e3 m/s, giving a KE of K2 = 2e6*M joules, which is an increase of 1.5e6*M joules, creating 1e6 joules of "free" energy with respect to B. With a rocket, that energy wouldn't appear since is has to spend energy to accelerate the reaction mass and it masses less afterwards. I worked all out with a friend for fun when we were building MT perpetual motion machines. (So I'm weird - sue me) W. Dow Rieder When the only tool you have is a hammer, all your problems start to look like nails...