This is version 2 of my nuclear power plant table.
As suggested, I've increased the efficiency of the high tech fusion
and antimatter plants and I've also included a different fuel types
for fission power plants.
I've been told that 5% enrichment is only good for civilian reactors,
military reactors use fuel enriched to up to 60%.
Enrichment would affect three areas. First, a fission reaction can
start more easily in higher enriched fuel (the "critical mass" is lower) so
the reactor can be made smaller. Second, for the same power output,
the fuel would last longer as there's more fuel to use in the same volume.
With the third, I'm not sure if higher enrichment would also lead to a
higher power output per volume of powerplant, so I haven't used it.
There are now different types of radioactives as fuel, with enrichment
rates of 5, 10, 20, 40 and 60%. I've given them a consumtion rate as in
the low tech supplement in Challenge 61. The 5% enriched radioactives
are the ones we know from MTrav, so their consumtion rate is set to 1.
The consumtion rates of the other types are simply one-half, one-forth,
one-eigth and one-twelweth of the standard type.
The reactor on the table is for 5% enriched fuel, to figure out
the minimum size of fission reactors using other types of radioactives,
multiply the minimum size of the standard reactor by the consumption
rate of the used radioactives type.
I haven't figured out the excat formuals so I've used straight
linear assumptions. These are almost certainly wrong, but I hope that
the basic assumptions are correct.
Maybe someone can give me the correct formulas so I can come up
with a final more or less correct version of the table.
So here's the revised table.
Type |TL| Wt|Price| Min Vol | Pow | Fuel| Fuel Type | Efficiency
===============================================================================
Fission | 6| 8 | 0.1 | 50.00 | 1.0 | 1.3 | Radioactives | ----
Fission | 8| 6 | 0.1 | 20.00 | 1.5 | 1.5 | Radioactives | ----
- - -----------------------------------------------------------------------------
Early Fusion| 9| 6 | 0.2 | 20.00 | 2.0 | 50.0 | Deuterium | 29%
Early Fusion|10| 5 | 0.2 | 4.00 | 2.0 | 40.0 | Deuterium | 36% - 13%
Early Fusion|11| 4 | 0.2 | 1.00 | 2.0 | 30.0 | Deuterium | 48% - 16%
- - -----------------------------------------------------------------------------
Fusion |12| 4 | 0.2 | 10.00 | 3.0 | 25.0 | Hydrogen | 24% - 16%
Fusion |13| 3 | 0.2 | 2.00 | 4.0 | 25.0 | Hydrogen | 32% - 11%
Fusion |14| 3 | 0.2 | 0.40 | 5.0 | 25.0 | Hydrogen | 42% - 6%
Fusion |15| 2 | 0.2 | 0.10 | 6.0 | 25.0 | Hydrogen | 50% - 5%
Fusion |16| 1 | 0.2 | 0.08 | 7.0 | 25.0 | Hydrogen | 58% - 5%
- - ----------------------------------------------------------------------------
Antimatter |17| 6 | 0.5 | 8.00 | 500 | 0.3 | Antimatter | 58%
Antimatter |18| 5 | 0.5 | 1.00 | 1000 | 0.6 | Antimatter | 58%
Antimatter |19| 4 | 0.5 | 0.50 | 2500 | 1.5 | Antimatter | 58%
Antimatter |20| 3 | 0.5 | 0.10 | 15000 | 9.0 | Antimatter | 58%
Antimatter |21| 2 | 0.5 | 0.02 | 50000 | 30.0 | Antimatter | 58%
===============================================================================
Wt is in tons per Kl of plant. Price is in MCr per Kl of plant.
Minimum Volume is in Kl. Pow is power output per Kl of plant.
Fuel is fuel usage in liter per year per Kl of plant.
Efficiency is the efficiency of the plants of the given level. The right
number is the efficiency for the largest plant (14+ Kl) and the left
number is the efficiency for the smallest possible plant for the given TL.
And here's the fuel table
Type | Weight | Consumption Rate | Price |
========================================================
Radioactives (5) | 12.5 | 1 | 75000 |
Radioactives (10) | 12.5 | 0.5 | 90000 |
Radioactives (20) | 12.5 | 0.25 | 130000 |
Radioactives (40) | 12.5 | 0.125 | 175000 |
Radioactives (60) | 12.5 | 0.083 | 225000 |
Deuterium | 0.14 | 1 | 350 |
========================================================
Weight is in tons per KL. Price in Cr per KL.
NOTES:
Deuterium Purification plants:
Purification of deuterium needs an extra stage to seperate the
deuterium atoms from the ordinary hydrogen atoms.
For deuterium purification plants, multiply minimum volume by 3,
power consumption by 5 and price by 2.
Klaus
- --
/ Klaus Moeller, Leiteweg 2, 2940 Wilhelmshaven, West - Germany \
< [email removed] [email removed] >
\ security is an exercise in applied paranoia /