Re: Spacecraft drives
In reply to #913 Spacecraft drives by Dana Carson
So you want a ship that is 30% fuel to be able to reach 4% of c? ok, the mass-ratio of the ship is: Mr = 1/.7 = 1.428... the final velocity (.04 c) is: Vb = Ve * ln(Mr) .04 c = Ve * ln(1.428..) .04c = Ve * .03566... 1.2e7 = Ve * .03566.. 3.36e7 = Ve So we need an exhaust velocity of bwtter than 11% of c! Isp = Ve * g Isp = 3.36e7 / 9.8 Isp = 3.4e6 Now the good news. Wer have engines *now* that can do this. The bad news is that they are ion drives with a thrust measured in *hundredths* of a g... <sigh>. I suspect that you won't get a *fusion* drive to do this well, as the "standard" 6e5 figure is likely figured by assuming *all* the energy released in the fusion reaction is deposited in the exhaust of helium. You *can't* improve that. Not without changing it into something other than a fusion drive. All opinions and material above is the responsibility of the originator. Submissions: [email removed], or [email removed] Administrator: [email removed] (James Perkins) The TML is made possible by facilities provided by Tektronix, Inc.