Operating System: HP-UX A.B7.00 U
Organization: AT&T-BL, Red Hill System Administration Group (HRSAG)
Location: HR 2C119
Phone: [phone removed]
Return-receipt:
X-Mailer: ELM [version 2.3 PL5]
If I ever figure out these blasted rules.....
How do you calculate the amount of fuel those darn power plants
need using the MegaT rules? I won't even repeat the figure I came
up with... it was ridiculus!
Here's the scenario:
A 2000T ship (volume 27000kl, Weight 600, etc.)
Jump 3, 3G manuever drives...
What I figured out so far (and poke holes here where needed) is this:
To obtain Jump 3 with this ship I need:
80 Jump units, for a total volume of 1080kl, and a weight
of 2160 tons. This would need 800kl of fuel (I want this
ship capable of 2 jumps at jump 3.)
So far so good... ( I think )
To get 3G of manuever I need:
160 Maneuver drive units, for a total volume of 2160kl,
and a weight of 5600T. Power required would be 11,200MW.
Now here is where I get screwed up:
I want there to be double the amount of power available than
what engineering needs for agility considerations. Therefore I
want my powerplant to generate 22,400MW. Looking at the charts
I find that I need 3734 fusion power plant units at a volume of
3734kl, and figuring out fuel I'm not so sure about...
Rob? Metlay? Anybody out there want to help a High Guard refugee?
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" Peter L. Berghold " INTERNET: [email removed] "+1[phone removed] "
" System Adminstrator" BIX : peteb """"""""""""""""""""
" AT&T, HRSAG " DELPHI : berghold """"""""""""""""""""""""""""""
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